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Solenoid Coil Inductance & Stored Magnetic Energy Calculator

Calculate solenoid coil inductance (Henrys, mH, μH), stored magnetic energy (Joules/mJ), magnetic flux density (B Tesla), and ferrite core permeability.

Calculated Results

Calculated Coil Inductance (L = μ₀μrN²A / l)
693.9 μH (0.694 mH)
Stored Magnetic Energy: 2.17 Millijoules (mJ)
Stored Energy (E = ½ L I²)
2.168 mJ (Joules × 10⁻³)
Internal Magnetic Flux Density (B)
9.82 Gauss (0.982 mT)
Cross-Sectional Area (A)
7.07 cm² (706.9 mm²)
Coil Turn Density (n = N/l)
3,125 turns / meter
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Frequently Asked Questions

What is the formula for solenoid coil inductance?

Formula: L = (mu_0 × mu_r × N^2 × A) / l, where mu_0 is the permeability of free space (4π × 10^-7 H/m), mu_r is relative core permeability, N is turn count, A is cross-sectional area (π r^2), and l is coil length.

Why does inductance scale with the square of the turns (N²)?

Doubling the number of turns doubles the magnetic field strength B inside the coil and simultaneously doubles the total magnetic flux linkages, multiplying total inductance by a factor of 4 (N^2).

How does an iron or ferrite core amplify inductance?

Ferromagnetic materials have high relative permeability (μr from 100 to over 2,000). Inserting a ferrite core concentrates magnetic flux lines, increasing coil inductance thousands of times without adding extra copper wire.

What is the magnetic energy stored in an inductor?

Energy formula: E = 0.5 × L × I^2 (in Joules). Unlike capacitors which store potential energy in an electric field between plates, inductors store kinetic energy dynamically in their surrounding magnetic field.